PHP function to convert time to ago format

Here i am sharing a cool PHP function that will enable your online and social application using time ago function, is and understandable easy to implement into your program, it accept PHP time() function, datetime, and  date, but only time() function will give you the correct answer to your question,

I also used this on my jquery instant shoutout system

 and my last tutorial on jquery instant messaging system

Most of the social media like facebook do also use this on their site.

The following function will convert the time stamp to time ago like 5 secs ago, 1 hour ago, 1 day ago, 2 days ago etc.

 Time Ago PHP Function

time_function,php

<br /> <?php function time_passed($timestamp){ //type cast, current time, difference in timestamps $timestamp = (int) $timestamp; $current_time = time(); $diff = $current_time - $timestamp; //intervals in seconds $intervals = array ( 'year' => 31556926, 'month' => 2629744, 'week' => 604800, 'day' => 86400, 'hour' => 3600, 'minute'=> 60<br /> );<br /> <br /> //now we just find the difference<br /> if ($diff == 0)<br /> {<br /> return 'just now';<br /> } <br /> <br /> if ($diff < 60) { return $diff == 1 ? $diff . ' second ago' : $diff . ' seconds ago'; } if ($diff >= 60 && $diff < $intervals['hour']) { $diff = floor($diff/$intervals['minute']); return $diff == 1 ? $diff . ' minute ago' : $diff . ' minutes ago'; } if ($diff >= $intervals['hour'] && $diff < $intervals['day']) { $diff = floor($diff/$intervals['hour']); return $diff == 1 ? $diff . ' hour ago' : $diff . ' hours ago'; } if ($diff >= $intervals['day'] && $diff < $intervals['week']) { $diff = floor($diff/$intervals['day']); return $diff == 1 ? $diff . ' day ago' : $diff . ' days ago'; } if ($diff >= $intervals['week'] && $diff < $intervals['month']) { $diff = floor($diff/$intervals['week']); return $diff == 1 ? $diff . ' week ago' : $diff . ' weeks ago'; } if ($diff >= $intervals['month'] && $diff < $intervals['year']) { $diff = floor($diff/$intervals['month']); return $diff == 1 ? $diff . ' month ago' : $diff . ' months ago'; } if ($diff >= $intervals['year'])<br /> {<br /> $diff = floor($diff/$intervals['year']);<br /> return $diff == 1 ? $diff . ' year ago' : $diff . ' years ago';<br /> }<br /> }<br /> <br /> ?><br />

Now here is an example to call your function

Calling the function is the simple part (assuming of course your dates are properly formatted), and can be done inline with your scripts using the example below:

Example calling function:

<br /> <?php $time=1445411900; echo time_passed($time); ?><br />

You can include time_function.php i your script to work perfectly